The compound A, C_{8}H_{8}O_{2}, reacts with | vedclass

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(B) Compound $A$ $(C_{8}H_{8}O_{2})$ undergoes cross-Aldol condensation with acetophenone to form a single product. This implies $A$ is an aldehyde wi

Vedclass · Accepted Answer

$4-$methoxy benzaldehyde

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(B) Compound $A$ $(C_{8}H_{8}O_{2})$ undergoes cross-Aldol condensation with acetophenone to form a single product. This implies $A$ is an aldehyde without $\alpha$-hydrogens, such as $4-$methoxybenzaldehyde $(p-CH_3OC_6H_4CHO)$.When $4-$methoxybenzaldehyde reacts with conc. $NaOH$, it undergoes the Cannizzaro reaction because it lacks $\alpha$-hydrogens.The reaction produces $4-$methoxybenzyl alcohol $(p-CH_3OC_6H_4CH_2OH)$ and $4-$methoxybenzoate ion $(p-CH_3OC_6H_4COO^-)$.Therefore, compound $A$ is $4-$methoxybenzaldehyde.

The compound $A$, $C_{8}H_{8}O_{2}$, reacts with acetophenone to form a single product via cross-Aldol condensation. The compound $A$ on reaction with conc. $NaOH$ forms a substituted benzyl alcohol. Identify compound $A$.

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