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(B) The given reaction is the Kolbe-Schmitt reaction. In this reaction,sodium phenoxide reacts with carbon dioxide $(CO_2)$ at a temperature of $390 \

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Sodium salicylate

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(B) The given reaction is the Kolbe-Schmitt reaction. In this reaction,sodium phenoxide reacts with carbon dioxide $(CO_2)$ at a temperature of $390 \ K$ and high pressure to form sodium phenyl carbonate as an intermediate,which then undergoes rearrangement to form sodium salicylate $(X)$. Finally,acidification with $HCl$ yields salicylic acid. Thus,the compound $X$ is sodium salicylate.

The compound $X$ in the reaction is

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