The compound forms nitroso amines when the substituents are
- A$R_1 = CH_3, R_2 = R_3 = H$
- B$R_1 = R_2 = H, R_3 = C_2H_5$
- C$R_1 = H, R_2 = R_3 = CH_3$
- D$R_1 = CH_3, R_2 = C_2H_5, R_3 = H$
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Similar Questions
Explain the carbylamine reaction.
Medium
View SolutionAmines are basic in nature because:
Medium
View SolutionWhich one of the following gives the most stable diazonium salt?
Match List $I$ with List $II$:
List $I$ (Amines) List $II$ $(pK_{b})$ $A$. Aniline $I$. $3.25$ $B$. Ethanamine $II$. $3.00$ $C$. $N$-Ethylethanamine $III$. $9.38$ $D$. $N,N$-Diethylethanamine $IV$. $3.29$
Choose the correct answer from the options given below:
| List $I$ (Amines) | List $II$ $(pK_{b})$ |
| $A$. Aniline | $I$. $3.25$ |
| $B$. Ethanamine | $II$. $3.00$ |
| $C$. $N$-Ethylethanamine | $III$. $9.38$ |
| $D$. $N,N$-Diethylethanamine | $IV$. $3.29$ |
Choose the correct answer from the options given below:
DifficultJEE MAIN 2023
View SolutionMatch the following reactions of benzene diazonium chloride $(ArN_2^{+} Cl^{-})$ given in Column-$I$ with the reagents given in Column-$II$:
Column-$I$ Column-$II$ $(A)$ $ArN_2^{+} Cl^{-} \rightarrow ArOH$ $(p)$ $HBF_4 / NaNO_2, \Delta$ $(B)$ $ArN_2^{+} Cl^{-} \rightarrow ArNO_2$ $(q)$ $H_2 O$ $(C)$ $ArN_2^{+} Cl^{-} \rightarrow ArH$ $(r)$ $HBF_4, \Delta$ $(D)$ $ArN_2^{+} Cl^{-} \rightarrow ArF$ $(s)$ $CH_3CH_2OH$
| Column-$I$ | Column-$II$ |
| $(A)$ $ArN_2^{+} Cl^{-} \rightarrow ArOH$ | $(p)$ $HBF_4 / NaNO_2, \Delta$ |
| $(B)$ $ArN_2^{+} Cl^{-} \rightarrow ArNO_2$ | $(q)$ $H_2 O$ |
| $(C)$ $ArN_2^{+} Cl^{-} \rightarrow ArH$ | $(r)$ $HBF_4, \Delta$ |
| $(D)$ $ArN_2^{+} Cl^{-} \rightarrow ArF$ | $(s)$ $CH_3CH_2OH$ |
Medium
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