The compound most likely to decolourize a sol | vedclass

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Question

(C) The correct answer is $C$. $CH_3-CH=CH-CH_2-CH_3$ is an alkene (pent$-2-$ene). Alkenes contain a carbon-carbon double bond,which undergoes oxidati

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$CH_3-CH=CH-CH_2-CH_3$

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(C) The correct answer is $C$. $CH_3-CH=CH-CH_2-CH_3$ is an alkene (pent$-2-$ene). Alkenes contain a carbon-carbon double bond,which undergoes oxidation with cold dilute alkaline $KMnO_4$ (Baeyer's reagent) to form vicinal diols,resulting in the decolourization of the purple $KMnO_4$ solution. Option $A$ is an alkane,option $B$ is naphthalene (an aromatic hydrocarbon),and option $D$ is an alkane,none of which react with cold dilute $KMnO_4$ under standard conditions.

The compound most likely to decolourize a solution of potassium permanganate is

Similar Questions

Compound $(A)$ is formed by the reaction of cyclooctatetraene with $(3 \text{ mole})$ of $CH_2I_2$ in the presence of $Zn/Cu$. Identify compound $(A)$.

The compounds that will give an isomer of $2,2$-dimethylpropane on catalytic hydrogenation are:
$(1)$ $CH_3-CH=C(CH_3)_2$
$(2)$ $CH_3-CH=CH-CH_3$
$(3)$ $CH_3-CH=CH-CH_2-CH_3$
$(4)$ $CH_3-C(CH_3)=C(CH_3)-CH_3$

In the given selective hydrogenation,which combination is incorrect?

Which of the following compounds will give $3, 5-$dimethyl$-6-$oxooctanal on reductive ozonolysis?

$CH_3-CH=CH_2 + NOCl \rightarrow P$
Identify the adduct.

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