The compound that readily tautomerises is

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(A) Tautomerism requires the presence of an $\alpha$-hydrogen atom adjacent to a carbonyl group. Compounds with an active methylene group $(-CH_2-)$ f

Vedclass · Accepted Answer

$CH_3COCH_2CO_2C_2H_5$

Vedclass · Answer

(A) Tautomerism requires the presence of an $\alpha$-hydrogen atom adjacent to a carbonyl group. Compounds with an active methylene group $(-CH_2-)$ flanked by two electron-withdrawing carbonyl groups (like in $\beta$-keto esters) undergo tautomerization most readily due to the stabilization of the resulting enol form by resonance and intramolecular hydrogen bonding. In $CH_3COCH_2CO_2C_2H_5$ (ethyl acetoacetate),the methylene group is between two carbonyl groups,making it highly acidic and prone to tautomerization. Therefore,the correct option is $A$.

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