The compound that will react most readily wit | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction involves a nucleophilic substitution $(S_N2)$ where $OH^-$ acts as the nucleophile.In $(CH_3)_4N^+I^-$,the quaternary ammonium salt a

Vedclass · Accepted Answer

$(CH_3)_4N^{+}I^{-}$

Vedclass · Answer

(A) The reaction involves a nucleophilic substitution $(S_N2)$ where $OH^-$ acts as the nucleophile.In $(CH_3)_4N^+I^-$,the quaternary ammonium salt acts as a good leaving group (trimethylamine,$(CH_3)_3N$) because the positive charge on the nitrogen atom makes the attached methyl group highly electrophilic.$(CH_3)_4N^+I^- + OH^- \rightarrow CH_3OH + (CH_3)_3N + I^-$.This reaction proceeds readily due to the high reactivity of the methyl group attached to the positively charged nitrogen atom.

The compound that will react most readily with $NaOH$ to form methanol is

Similar Questions

Which compound is virtually non-basic?

Chloroform when treated with aniline and alcoholic $KOH$ gives:

Write the reactions for the final alkylation product of aniline with an excess of methyl iodide in the presence of sodium carbonate solution.

Identify the compound that will react with Hinsberg's reagent to give a solid which dissolves in alkali.

Which of the following statements about aniline is false?

Vedclass Test Series

Exam Paper Generator

Online Exam Module