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(B) $CH_3COCl$ (acetyl chloride) is highly reactive and hydrolyzes to form $CH_3COOH$ (acetic acid) even at $25^{\circ} C$. Acetic acid is a stronger

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$CH_3COCl$

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(B) $CH_3COCl$ (acetyl chloride) is highly reactive and hydrolyzes to form $CH_3COOH$ (acetic acid) even at $25^{\circ} C$. Acetic acid is a stronger acid than carbonic acid $(H_2CO_3)$, so it reacts with $NaHCO_3$ to evolve $CO_2$ gas. The reaction is: $CH_3COCl + H_2O \longrightarrow CH_3COOH + HCl$ $CH_3COOH + NaHCO_3 \longrightarrow CH_3COONa + H_2O + CO_2 \uparrow$ Thus, option $(B)$ is the correct answer.

The compound, which evolves carbon dioxide on treatment with an aqueous solution of sodium bicarbonate at $25^{\circ} C$, is

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