(C) The molarity formula is given by $Y = \frac{X \times 1000}{m \times V}$.Given $m = 106$, $V = 100 \ mL$, and $Y$ is the molarity.Substituting the

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(C) The molarity formula is given by $Y = \frac{X \times 1000}{m \times V}$.Given $m = 106$, $V = 100 \ mL$, and $Y$ is the molarity.Substituting the values: $Y = \frac{X \times 1000}{106 \times 100} = \frac{10X}{106}$.Rearranging gives $106Y = 10X$.For option $C$: $X = 1.06$ and $Y = 0.1$.$106(0.1) = 10.6$ and $10(1.06) = 10.6$.Since both sides are equal, option $C$ is correct.

Class 11 Chemistry Some Basic Concepts of Chemistry Chemical stoichiometry

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The concentration of a $100 \ mL$ solution containing $X \ g$ of $Na_2CO_3$ (molecular weight $= 106$) is $Y \ M$. The values of $X$ and $Y$ are respectively.

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A
$2.12, 0.05$
B
$1.06, 0.2$
C
$1.06, 0.1$
D
$2.12, 0.1$

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Some Basic Concepts of Chemistry

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Chemical stoichiometry

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The concentration of a $100 \ mL$ solution containing $X \ g$ of $Na_2CO_3$ (molecular weight $= 106$) is $Y \ M$. The values of $X$ and $Y$ are respectively.

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