The conditional statement $(p \wedge q) \implies p$ is:

The negation of the statement $(p \wedge q) \rightarrow (\sim p \vee r)$ is

Consider the following statements:
$r: \text{If } p \to q \text{ is false, then } p \lor q \text{ is false.}$
$s: \text{If } p \leftrightarrow q \text{ is false, then } p \lor q \text{ is false.}$
The truth values of $r \to s$ and $s \to r$ are respectively . . . . . .

Consider the following statements:
Statement $1$: If a quadrilateral is a square,then all of its sides are equal.
Statement $2$: If all the sides of a quadrilateral are equal,then it is a square.

The statement "If $3^2 = 10$ then $I$ get second prize" is logically equivalent to

The contrapositive of $(\sim p \wedge q) \rightarrow (q \wedge \sim r)$ is