The consecutive reaction $X$ $\longrightarrow Y$ $\longrightarrow Z$ takes place in a closed container. Initially,the container has $A_{0}$ moles of $X$ (and no $Y$ and $Z$). The plot of total moles of the constituents in the container as a function of time will be:

The reaction of ozone with oxygen atoms in the presence of chlorine atoms can occur by a two-step process shown below:
$O_{3(g)} + Cl_{(g)}^{\bullet} \to O_{2(g)} + ClO_{(g)}^{\bullet}$ ..... $(i)$ $K_i = 5.2 \times 10^9 \ L \ mol^{-1} \ s^{-1}$
$ClO_{(g)}^{\bullet} + O_{(g)}^{\bullet} \to O_{2(g)} + Cl_{(g)}^{\bullet}$ ..... $(ii)$ $K_{ii} = 2.6 \times 10^{10} \ L \ mol^{-1} \ s^{-1}$
The closest rate constant for the overall reaction
$O_{3(g)} + O_{(g)}^{\bullet} \to 2O_{2(g)}$ is ........... $L \ mol^{-1} \ s^{-1}$

Match the column $I$ with column $II$ :

$a$. Rate constant for first order reaction	$i$. $mol \ lit^{-1} \sec^{-1}$
$b$. Molarity	$ii$. $\frac{k \times 1000}{M}$
$c$. Rate constant for zero order reaction	$iii$. $second^{-1}$
$d$. Limiting molar conductivity	$iv$. $\frac{\text{moles of solute}}{\text{Volume of solution (lit)}}$

For a chemical reaction,the temperature is increased from $25\,^{\circ}C$ to $55\,^{\circ}C$. The rate of reaction will change by a factor of (Assume $\mu = 3$).

For the following parallel chain reaction,what will be the value of the overall half-life of $A$ in minutes?
Given that $\frac{[B]_t}{[C]_t} = \frac{16}{9}$
$A \xrightarrow{k_1 = 2 \times 10^{-3} \ s^{-1}} 4B$
$A \xrightarrow{k_2} C$

For a chemical reaction, half-life period $(t_{1/2})$ is $10 \ minutes$. How much reactant will be left after $20 \ minutes$ if one starts with $100 \ moles$ of reactant and the order of the reaction is $(i)$ zero, $(ii)$ one, and $(iii)$ two?