The conversion of $CH_{3}CH_{2}COOH$ to the product shown below can be accomplished by:
$CH_{3}CH_{2}CH(OCH_{2}CH_{2}O)$

How will you bring about the following conversions in not more than two steps?
$(i)$ Propanone to Propene
$(ii)$ Benzoic acid to Benzaldehyde
$(iii)$ Ethanol to $3-$Hydroxybutanal
$(iv)$ Benzene to $m-$Nitroacetophenone
$(v)$ Benzaldehyde to Benzophenone
$(vi)$ Bromobenzene to $1-$Phenylethanol
$(vii)$ Benzaldehyde to $3-$Phenylpropan$-1-$ol
$(viii)$ Benzaldehyde to $\alpha-$Hydroxyphenylacetic acid
$(ix)$ Benzoic acid to $m-$Nitrobenzyl alcohol

What are $A, B$ and $C$ in the following reactions?
Phthalic acid $+\, NH_3 \rightarrow A \xrightarrow{\Delta} B \xrightarrow{\text{High temperature}} C$

Match List-$I$ and List-$II$.

List-$I$	List-$II$
$(a)$ $R-COCl \to R-CHO$	$(i)$ $Br_2 / NaOH$
$(b)$ $R-CH_2-COOH \to R-CH(Cl)-COOH$	$(ii)$ $H_2 / Pd-BaSO_4$
$(c)$ $R-CONH_2 \to R-NH_2$	$(iii)$ $Zn(Hg) / \text{Conc. } HCl$
$(d)$ $R-CO-CH_3 \to R-CH_2-CH_3$	$(iv)$ $Cl_2 / \text{Red } P, H_2O$

Choose the correct answer from the options given below:

In the given reaction $[X]$ will be :

The product $(A)$ obtained is: