The coordinates of the midpoint of the line segment joining the points $(20, 10)$ and $(6, 8)$ are:

$(0, 0), (3.1, 0)$ and $(0, 4.5)$ are the vertices of $\ldots \ldots \ldots \ldots$ triangle.

Show that the centroid of the triangle with vertices $(a, b-c)$,$(b, c-a)$,and $(c, a-b)$ lies on the $X$-axis.

If the distance between $A(-4, -3)$ and $B(6, a)$ is $10$,then $a = \ldots \ldots \ldots . . .$

$\overline{AB}$ is given and $P$ is a point such that $A-P-B$. If $P$ divides $\overline{AB}$ from $A$ in ratio $2:3$,then $P$ divides $\overline{AB}$ from $B$ in ratio $\dots$.

If $P(1, 12)$ divides the line segment $\overline{AB}$ starting from $A$ in the ratio $2:1$ and $A(3, 8)$,then the coordinates of $B$ are $\ldots \ldots$