The coordination number of chromium in K[Cr(H | vedclass

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(C) The coordination number is defined as the number of ligand donor atoms to which the metal is directly bonded.In the complex $[Cr(H_2O)_2(C_2O_4)_2

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(C) The coordination number is defined as the number of ligand donor atoms to which the metal is directly bonded.In the complex $[Cr(H_2O)_2(C_2O_4)_2]^-$,the ligands are:$1$. Two $H_2O$ molecules,which are monodentate ligands (each donates $1$ pair of electrons).$2$. Two $C_2O_4^{2-}$ (oxalate) ions,which are bidentate ligands (each donates $2$ pairs of electrons).Calculation: $(2 	imes 1) + (2 	imes 2) = 2 + 4 = 6$.Therefore,the coordination number of $Cr$ is $6$.

The coordination number of chromium in $K[Cr(H_2O)_2(C_2O_4)_2]$ is

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