The coordination number,oxidation number,numb | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $1$. Coordination number: $NH_3$ is a monodentate ligand $(4 	imes 1 = 4)$ and $CO_3^{2-}$ is a bidentate ligand $(1 	imes 2 = 2)$. Total coordi

Vedclass · Accepted Answer

$6, 3, 6, 0$

Vedclass · Answer

(C) $1$. Coordination number: $NH_3$ is a monodentate ligand $(4 	imes 1 = 4)$ and $CO_3^{2-}$ is a bidentate ligand $(1 	imes 2 = 2)$. Total coordination number = $4 + 2 = 6$.$2$. Oxidation number: Let the oxidation state of $Co$ be $x$. The complex is $[Co(NH_3)_4CO_3]ClO_4$. The charge on $ClO_4$ is $-1$,so the complex ion $[Co(NH_3)_4CO_3]^+$ has a charge of $+1$. Thus,$x + 4(0) + 1(-2) = +1$,which gives $x = +3$.$3$. Number of electrons in $d$-orbital: $Co$ $(Z=27)$ has the configuration $[Ar] 3d^7 4s^2$. $Co^{3+}$ has the configuration $[Ar] 3d^6$. Thus,there are $6$ electrons in the $d$-orbital.$4$. Number of unpaired electrons: In the presence of strong field ligands like $NH_3$ and $CO_3^{2-}$,the $6$ electrons in the $3d$ orbitals of $Co^{3+}$ pair up in the $t_{2g}$ set. Therefore,the number of unpaired electrons is $0$.

The coordination number,oxidation number,number of electrons in $d$-orbital,and number of unpaired electrons respectively in the complex $[Co(NH_3)_4CO_3]ClO_4$ are . . . . . . .

Similar Questions

The magnetic moment of a metal ion from the first transition series is $2.83 \, BM$. How many unpaired electrons are present in this ion?

Consider the complexes:
$I$. $[Pd(NH_3)_2 ClBr]$
$II$. $[Pd(NH_3)_2 Cl_2]$
$III$. $[Pd(en) Cl_2]$
$IV$. $[Pd(en) ClBr]$
$V$. $[Pd(en)_2 Cl_2]$
(en = ethylenediamine)
The total number of geometrical isomers of $(I)$ is the same as the total number of geometrical isomers of:

The magnitude of magnetic moment (spin only) of $[NiCl_4]^{2-}$ will be ........ $B.M.$

Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers: $Mn = 25$; $Fe = 26$)
$(A)$ $[FeF_{6}]^{3-}$
$(B)$ $[Fe(CN)_{6}]^{3-}$
$(C)$ $[MnCl_{6}]^{3-}$ (high spin)
$(D)$ $[Mn(CN)_{6}]^{3-}$

Which of the following can show optical isomerism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module