(B) For a $1^{st}$-order reaction,the half-life is given by $t_{1/2} = \frac{0.693}{k}$,which is independent of the initial concentration $[A]_0$. For

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the half-life of a $1^{st}$-order reaction does not depend on $[A]_0$; the half-life of a $2^{nd}$-order reaction does depend on $[A]_0$

(B) For a $1^{st}$-order reaction,the half-life is given by $t_{1/2} = \frac{0.693}{k}$,which is independent of the initial concentration $[A]_0$. For a $2^{nd}$-order reaction,the half-life is given by $t_{1/2} = \frac{1}{k[A]_0}$,which is inversely proportional to the initial concentration $[A]_0$.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

The correct difference between $1^{st}$-order and $2^{nd}$-order reaction is that:

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A
the rate of a $1^{st}$-order reaction does not depend on reactant concentration; the rate of a $2^{nd}$-order reaction does depend on reactant concentrations
B
the half-life of a $1^{st}$-order reaction does not depend on $[A]_0$; the half-life of a $2^{nd}$-order reaction does depend on $[A]_0$
C
$1^{st}$-order reaction can be catalyzed; a $2^{nd}$-order reaction cannot be catalyzed.
D
the rate of a $1^{st}$-order reaction does depend on reactant concentrations; the rate of a $2^{nd}$-order reaction does not depend on reactant concentrations

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Class 12

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Chemical Kinetics

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Rate law , Rate constant , Order of Reaction and Molecularity

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What is the order of reaction if the unit of the rate constant is $s^{-1}$?

EasyMHT CET 2022

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In a reaction,the concentration of reactant is increased two times and three times,then the increases in the rate of reaction were four times and nine times respectively. The order of reaction is:

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Identify the correct statement regarding the order of reaction from the following.

MediumMHT CET 2026

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For a chemical reaction $A + B \rightarrow \text{Product}$,the order is $1$ with respect to $A$ and $B$.
Rate $(mol \ L^{-1} \ s^{-1})$ $[A]$ $(mol \ L^{-1})$ $[B]$ $(mol \ L^{-1})$
$0.10$ $20$ $0.5$
$0.40$ $x$ $0.5$
$0.80$ $40$ $y$

What is the value of $x$ and $y$?

Rate $(mol \ L^{-1} \ s^{-1})$	$[A]$ $(mol \ L^{-1})$	$[B]$ $(mol \ L^{-1})$
$0.10$	$20$	$0.5$
$0.40$	$x$	$0.5$
$0.80$	$40$	$y$

MediumJEE MAIN 2023

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Write the differential rate expression for the following reaction and determine its order of reaction:
$H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}$
$H_{2}O_{2} + IO^{-} \rightarrow H_{2}O + I^{-} + O_{2}$

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The correct difference between $1^{st}$-order and $2^{nd}$-order reaction is that:

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What is the order of reaction if the unit of the rate constant is $s^{-1}$?

In a reaction,the concentration of reactant is increased two times and three times,then the increases in the rate of reaction were four times and nine times respectively. The order of reaction is:

Identify the correct statement regarding the order of reaction from the following.

For a chemical reaction $A + B \rightarrow \text{Product}$,the order is $1$ with respect to $A$ and $B$.Rate $(mol \ L^{-1} \ s^{-1})$$[A]$ $(mol \ L^{-1})$$[B]$ $(mol \ L^{-1})$$0.10$$20$$0.5$$0.40$$x$$0.5$$0.80$$40$$y$What is the value of $x$ and $y$?

Write the differential rate expression for the following reaction and determine its order of reaction:$H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}$$H_{2}O_{2} + IO^{-} \rightarrow H_{2}O + I^{-} + O_{2}$

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For a chemical reaction $A + B \rightarrow \text{Product}$,the order is $1$ with respect to $A$ and $B$.
Rate $(mol \ L^{-1} \ s^{-1})$ $[A]$ $(mol \ L^{-1})$ $[B]$ $(mol \ L^{-1})$
$0.10$ $20$ $0.5$
$0.40$ $x$ $0.5$
$0.80$ $40$ $y$

What is the value of $x$ and $y$?

Write the differential rate expression for the following reaction and determine its order of reaction:
$H_{2}O_{2} + I^{-} \rightarrow H_{2}O + IO^{-}$
$H_{2}O_{2} + IO^{-} \rightarrow H_{2}O + I^{-} + O_{2}$