The correct increasing order of adjacent bond | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In $BF_3$,the central atom $B$ is $sp^2$ hybridized with a trigonal planar geometry,resulting in a bond angle of $120^{\circ}$.In $PF_3$,the centr

Vedclass · Accepted Answer

$ClF_3 < PF_3 < BF_3$

Vedclass · Answer

(C) In $BF_3$,the central atom $B$ is $sp^2$ hybridized with a trigonal planar geometry,resulting in a bond angle of $120^{\circ}$.In $PF_3$,the central atom $P$ is $sp^3$ hybridized with a trigonal pyramidal geometry. Due to the presence of one lone pair,the bond angle is compressed to approximately $96^{\circ}$.In $ClF_3$,the central atom $Cl$ is $sp^3d$ hybridized with a $T$-shaped geometry. Due to the presence of two lone pairs in the equatorial positions,the bond angle is further compressed to approximately $87^{\circ}$.Thus,the increasing order of bond angles is $ClF_3 (87^{\circ}) < PF_3 (96^{\circ}) < BF_3 (120^{\circ})$.

The correct increasing order of adjacent bond angle among $BF_3$,$PF_3$,and $ClF_3$ is:

Similar Questions

The shape of $H_3O^{+}$ ion is

Which of the following molecules does not have a lone pair of electrons in the valence shell of the central atom?

Which of the following pairs are isostructural?

The shape of a molecule of $NH_3$,in which the central atom contains a lone pair of electrons,is

The compound$(s)$ with $2$ lone pairs of electrons on the central atom is(are):
$(A)$ $BrF_5$
$(B)$ $ClF_3$
$(C)$ $XeF_4$
$(D)$ $SF_4$

Vedclass Test Series

Exam Paper Generator

Online Exam Module