The correct order for the rate of decarboxyla | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The rate of decarboxylation is directly proportional to the stability of the carbanion intermediate formed after the loss of $CO_2$.The $-NO_2$ gr

Vedclass · Accepted Answer

$IV > I > III > II$

Vedclass · Answer

(A) The rate of decarboxylation is directly proportional to the stability of the carbanion intermediate formed after the loss of $CO_2$.The $-NO_2$ group is a strong electron-withdrawing group ($-I$ and $-M$ effect),which stabilizes the carbanion.In compound $(IV)$,there are two $-NO_2$ groups (at ortho and para positions),providing maximum stabilization.In compound $(I)$,the $-NO_2$ group is at the ortho position,which provides strong stabilization due to the $-I$ effect.In compound $(III)$,the $-NO_2$ group is at the para position,providing stabilization via $-I$ and $-M$ effects,but it is further from the carbanion center compared to the ortho position.In compound $(II)$,the $-NO_2$ group is at the meta position,providing stabilization only via the $-I$ effect.Thus,the stability order of the carbanions is $(IV) > (I) > (III) > (II)$.Therefore,the correct order for the rate of decarboxylation is $IV > I > III > II$.

The correct order for the rate of decarboxylation of the following compounds with sodalime will be:

Similar Questions

Which type of the overlap of orbitals is involved in hyperconjugation?

Explain the delocalization of electrons in $CH_3-CH_2^+$ and $CH_3-CH=CH_2$.

Which of the following groups as $X$ will decrease the $pKa$ value of the given compound?

Which of the following compounds has the maximum enol content?

Vedclass Test Series

Exam Paper Generator

Online Exam Module