The correct order of Cl-O bond order is | vedclass

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(C) The bond order $(B.O.)$ can be calculated using the formula: $B.O. = 1 + \frac{	ext{number of double bonds}}{	ext{number of total bonds}}$.For $

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$ClO^- < ClO_2^- < ClO_3^- < ClO_4^-$

Vedclass · Answer

(C) The bond order $(B.O.)$ can be calculated using the formula: $B.O. = 1 + \frac{	ext{number of double bonds}}{	ext{number of total bonds}}$.For $ClO^-$: $Cl-O^-$,$B.O. = 1.0$.For $ClO_2^-$: $O-Cl-O^-$,resonance hybrid gives $B.O. = \frac{3}{2} = 1.5$.For $ClO_3^-$: $B.O. = \frac{5}{3} \approx 1.66$.For $ClO_4^-$: $B.O. = \frac{7}{4} = 1.75$.Thus,the correct order is $ClO^- < ClO_2^- < ClO_3^- < ClO_4^-$.

The correct order of $Cl-O$ bond order is

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