The correct order of acidity of the following | vedclass

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(D) Acidity depends on the stability of the conjugate base formed after the removal of a proton. The stability of the conjugate base is increased by e

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$II > I > III > IV$

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(D) Acidity depends on the stability of the conjugate base formed after the removal of a proton. The stability of the conjugate base is increased by electron-withdrawing groups ($-I$ effect) and decreased by electron-donating groups ($+I$ effect).$1$. In compound $II$,the $F_3C-$ group exerts a strong $-I$ effect,making it the most acidic.$2$. In compound $I$,the terminal alkyne hydrogen is acidic due to the $sp$ hybridized carbon.$3$. Compound $III$ is an internal alkyne with no acidic protons (no $C-H$ bond on the triple-bonded carbons),but if we consider the acidity of the $CH_3$ protons,they are less acidic than terminal alkynes.$4$. Compound $IV$ is an alkene,which is the least acidic among the given options.Thus,the correct order of acidity is $II > I > III > IV$.

The correct order of acidity of the following compounds is

$I. CH_3-C \equiv CH$

$II. F_3C-C \equiv CH$

$III. CH_3-C \equiv C-CH_3$

$IV. CH_3-CH=CH-CH_3$

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The correct order of acidity of the following compounds is $I. CH_3-C \equiv CH$ $II. F_3C-C \equiv CH$ $III. CH_3-C \equiv C-CH_3$ $IV. CH_3-CH=CH-CH_3$