The correct order of atomic radii of $C$,$Al$,and $S$ is

  • A
    $C < Al < S$
  • B
    $S < Al < C$
  • C
    $Al < S < C$
  • D
    $C < S < Al$

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Which has the highest value of ionic radius?

In period $4$ of the periodic table, the elements with the highest and lowest atomic radii are respectively:

Arrange the following elements in increasing order of their atomic radius: $Na$,$K$,$Mg$,$Rb$.

Among the isoelectronic ions $(O^{2-}, N^{3-}, Mg^{2+}, Na^{+})$,the ions with the least and the highest ionic radius are,respectively

The ionic radii of $F^{-}$ and $O^{2-}$ respectively are $1.33 \ \mathring{A}$ and $1.40 \ \mathring{A}$,while the covalent radius of $N$ is $0.74 \ \mathring{A}$. The correct statement for the ionic radius of $N^{3-}$ from the following is:

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