The correct order of basic strength of the fo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $I$. Piperidine is the most basic. The $N$ lone pair is in an $sp^3$ hybrid orbital,there is no resonance,and due to the $+I$ effect of the alkyl

Vedclass · Accepted Answer

$I > III > II > IV$

Vedclass · Answer

(A) $I$. Piperidine is the most basic. The $N$ lone pair is in an $sp^3$ hybrid orbital,there is no resonance,and due to the $+I$ effect of the alkyl group attached,it becomes more basic than $sp^3$ hybridized ammonia.$II$. In pyridine,the lone pair is in an $sp^2$ hybridized orbital. The $sp^2$ hybrid is smaller than $sp^3$,so there is a stronger attraction to the nucleus,making it less basic.$III$. $NH_3$ is more basic than aniline because in ammonia,the lone pair is localized and easily available for donation.$IV$. The basicity of aniline is lower than that of ammonia because in aniline,the lone pair of electrons on $N$ is involved in resonance with the benzene ring.Therefore,the correct order of basic strength is $I > III > II > IV$.

The correct order of basic strength of the following amines is

Similar Questions

Identify the final product $Z$ in the following reaction sequence:

When ethyl amine is heated with chloroform and alcoholic $KOH$,a compound with an offensive smell is obtained. This compound is

In the above reactions,product $A$ and product $B$ respectively are:

$A$ mixture of ethyl amine,chloroform,and alcoholic $KOH$ on heating gives:

Which of the following substances is more basic than aniline?

Vedclass Test Series

Exam Paper Generator

Online Exam Module