The correct order of basic strength of the fo | vedclass

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(C) To determine the basic strength,we analyze the nature of the compounds:$(I)$ $KOH$ is a strong base (alkali metal hydroxide).$(II)$ $Zn(OH)_2$ is

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$I > IV > II > III$

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(C) To determine the basic strength,we analyze the nature of the compounds:$(I)$ $KOH$ is a strong base (alkali metal hydroxide).$(II)$ $Zn(OH)_2$ is an amphoteric hydroxide.$(III)$ $HNO_3$ is a strong acid.$(IV)$ $Ca(OH)_2$ is a strong base (alkaline earth metal hydroxide).Comparing the basicity: $KOH$ (Group $1$) is a stronger base than $Ca(OH)_2$ (Group $2$). $Zn(OH)_2$ is amphoteric,meaning it acts as a weak base compared to strong bases but is more basic than the strong acid $HNO_3$.Therefore,the order of basic strength is $KOH > Ca(OH)_2 > Zn(OH)_2 > HNO_3$,which corresponds to $I > IV > II > III$.

The correct order of basic strength of the following compounds is:
$(I)$ $KOH$
$(II)$ $Zn(OH)_2$
$(III)$ $HNO_3$
$(IV)$ $Ca(OH)_2$

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The correct order of basic strength of the following compounds is:$(I)$ $KOH$$(II)$ $Zn(OH)_2$$(III)$ $HNO_3$$(IV)$ $Ca(OH)_2$