The correct order of basicity of oxides of va | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The basicity of oxides of a transition metal decreases as the oxidation state of the metal increases. In $V_2O_3$,the oxidation state of $V$ is $+

Vedclass · Accepted Answer

$V_2O_3 > V_2O_4 > V_2O_5$

Vedclass · Answer

(A) The basicity of oxides of a transition metal decreases as the oxidation state of the metal increases. In $V_2O_3$,the oxidation state of $V$ is $+3$. In $V_2O_4$,the oxidation state of $V$ is $+4$. In $V_2O_5$,the oxidation state of $V$ is $+5$. As the oxidation state increases,the acidic character increases and the basic character decreases. Therefore,the order of basicity is $V_2O_3 > V_2O_4 > V_2O_5$.

The correct order of basicity of oxides of vanadium is

Similar Questions

Which of the following will not form an amalgam?

The ${E^0}_{M^{3+}/M^{2+}}$ values for $Cr, Mn, Fe$ and $Co$ are $-0.41, +1.57, +0.77$ and $+1.97 \ V$ respectively. For which one of these metals is the change in oxidation state from $+2$ to $+3$ the easiest?

Which one of the following oxides is ionic?

Transition elements with lower oxidation states act as........

Write the chemical reactions of lanthanoids $(Ln)$ with the following:
$(1)$ With acid:
$2Ln + 6HCl \rightarrow 2LnCl_3 + 3H_2$
$(2)$ With halogens ($X_2$,where $X = F, Cl, Br, I$):
$2Ln + 3X_2 \rightarrow 2LnX_3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module