The correct order of boiling points of the fo | vedclass

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(A) The boiling point of isomeric alkanes decreases with increasing branching due to a decrease in the exposed surface area,which leads to weaker van

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$i > ii > iii$

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(A) The boiling point of isomeric alkanes decreases with increasing branching due to a decrease in the exposed surface area,which leads to weaker van der Waals forces.$n$-Hexane $(i)$ is a straight-chain alkane with the largest surface area,hence it has the highest boiling point.$2$-methylpentane $(ii)$ has one branch,reducing its surface area compared to $n$-hexane.$2,3$-dimethylbutane $(iii)$ has two branches,resulting in the most compact structure and the smallest surface area,hence it has the lowest boiling point.Therefore,the correct order is $i > ii > iii$.

The correct order of boiling points of the following molecules is:
$(i)$ $n$-Hexane
$(ii)$ $2$-methylpentane
$(iii)$ $2,3$-dimethylbutane

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The correct order of boiling points of the following molecules is:$(i)$ $n$-Hexane$(ii)$ $2$-methylpentane$(iii)$ $2,3$-dimethylbutane