The correct order of bond angles of the follo | vedclass

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(D) As we move down the group,the electronegativity of the central atom decreases and its atomic size increases. Due to the increase in the size of th

Vedclass · Accepted Answer

$H_2Te < H_2Se < H_2S < H_2O$

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(D) As we move down the group,the electronegativity of the central atom decreases and its atomic size increases. Due to the increase in the size of the central atom,the bond pairs of electrons are further away from the central atom,which reduces the bond pair-bond pair repulsion. Consequently,the bond angle decreases as we move down the group from $O$ to $Te$. The correct order of bond angles is: $H_2O (104.5^{\circ}) > H_2S (92.1^{\circ}) > H_2Se (91.0^{\circ}) > H_2Te (90.0^{\circ})$.

List-$I$ (Compound)	List-$II$ (Structure)
$A$. $ClF_3$	$1$. Square planar
$B$. $PCl_5$	$2$. Tetrahedral
$C$. $IF_5$	$3$. Trigonal bipyramidal
$D$. $CCl_4$	$4$. Square pyramidal
$E$. $XeF_4$	$5$. $T$-shaped

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $BrF_5$	$I$. $T$-shape
$B$. $H_2O$	$II$. See-saw
$C$. $ClF_3$	$III$. Bent
$D$. $SF_4$	$IV$. Square pyramidal

The correct order of bond angles of the following compounds is

Similar Questions

Match List-$I$ with List-$II$:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $BrF_5$ $I$. $T$-shape

$B$. $H_2O$ $II$. See-saw

$C$. $ClF_3$ $III$. Bent

$D$. $SF_4$ $IV$. Square pyramidal

The sum of the number of lone pairs of electrons present on the central atoms of $XeO_3$,$XeOF_4$,and $XeF_6$ is $.......$

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