The correct order of energies of d- orbitals | vedclass

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Question

(D) In a square planar complex,the metal ion is surrounded by four ligands in the $xy-$plane. Due to the presence of ligands along the $x$ and $y$ axe

Vedclass · Accepted Answer

$d_{x^2-y^2} > d_{xy} > d_{z^2} > d_{zx} = d_{yz}$

Vedclass · Answer

(D) In a square planar complex,the metal ion is surrounded by four ligands in the $xy-$plane. Due to the presence of ligands along the $x$ and $y$ axes,the $d_{x^2-y^2}$ orbital experiences the maximum repulsion and has the highest energy. The $d_{xy}$ orbital,which lies in the same plane as the ligands,has the next highest energy. The $d_{z^2}$ orbital,which has electron density along the $z-$axis,has lower energy than $d_{xy}$ but higher than the remaining orbitals. The $d_{yz}$ and $d_{zx}$ orbitals have the lowest energy as they are oriented away from the ligands. The correct order of energy is $d_{x^2-y^2} > d_{xy} > d_{z^2} > d_{zx} = d_{yz}$.

The correct order of energies of $d-$ orbitals of a metal ion in a square planar complex is:

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