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(B) According to Molecular Orbital Theory,for homonuclear diatomic molecules like $B_2, C_2,$ and $N_2$,the $2s-2p$ mixing causes the $\sigma 2p_z$ or

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$\sigma 1s < \sigma^* 1s < \sigma 2s < \sigma^* 2s < (\pi 2p_x = \pi 2p_y) < \sigma 2p_z < (\pi^* 2p_x = \pi^* 2p_y) < \sigma^* 2p_z$

Vedclass · Answer

(B) According to Molecular Orbital Theory,for homonuclear diatomic molecules like $B_2, C_2,$ and $N_2$,the $2s-2p$ mixing causes the $\sigma 2p_z$ orbital to have higher energy than the $\pi 2p_x$ and $\pi 2p_y$ orbitals.Therefore,the correct increasing order of energy for $N_2$ is $\sigma 1s < \sigma^* 1s < \sigma 2s < \sigma^* 2s < (\pi 2p_x = \pi 2p_y) < \sigma 2p_z < (\pi^* 2p_x = \pi^* 2p_y) < \sigma^* 2p_z$.

The correct order of energies of molecular orbitals of $N_2$ molecule is

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