The correct order of equatorial FSF bond angl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Bent's rule,the bond angle is inversely proportional to the $p$-character of the hybrid orbitals forming the bonds.$(I) \ SF_4$: The

Vedclass · Accepted Answer

$(I) > (II) > (III)$

Vedclass · Answer

(C) According to Bent's rule,the bond angle is inversely proportional to the $p$-character of the hybrid orbitals forming the bonds.$(I) \ SF_4$: The lone pair occupies an equatorial position in the trigonal bipyramidal geometry. The lone pair-bond pair repulsion compresses the equatorial $FSF$ bond angle to approximately $101^{\circ}$.$(II) \ OSF_4$: The highly electronegative oxygen atom is double-bonded to the sulfur atom. According to Bent's rule,the double bond prefers an orbital with more $s$-character,leaving more $p$-character for the $S-F$ bonds. This results in a smaller bond angle compared to $SF_4$.$(III) \ H_2CSF_4$: The $CH_2$ group is attached via a double bond. The presence of the $CH_2$ group further influences the hybridization,leading to an equatorial $FSF$ bond angle of approximately $97^{\circ}$.Comparing the effects,the bond angle decreases as the $p$-character of the $S-F$ bonds increases due to the presence of more electronegative or double-bonded substituents. The correct order is $(I) > (II) > (III)$.

The correct order of equatorial $FSF$ bond angle in the following compounds:
$(I) \ SF_4$ $(II) \ OSF_4$ $(III) \ H_2CSF_4$

Similar Questions

The correct sequence of decreasing bond angles for the following hydrides is:

The number of species from the following that have pyramidal geometry around the central atom is . . . . . . . . .
$S_2O_3^{2-}, SO_4^{2-}, SO_3^{2-}, S_2O_7^{2-}$

Identify the geometry of $TeF_4$ molecule from the following.

In which of the following pairs,the central atoms have the same number of lone pairs of electrons?

The isostructural molecules among $CO_2, SiO_2, SO_2, TeO_2, [NO_2]^{+}$ are

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The correct order of equatorial $FSF$ bond angle in the following compounds:$(I) \ SF_4$ $(II) \ OSF_4$ $(III) \ H_2CSF_4$