The correct order of equivalent conductance of $LiCl$, $NaCl$ and $KCl$ at infinite dilution is

At $291 \ K$,a saturated solution of $BaSO_4$ was found to have a specific conductivity of $3.648 \times 10^{-6} \ \Omega^{-1} \ cm^{-1}$ and that of the water used is $1.25 \times 10^{-6} \ \Omega^{-1} \ cm^{-1}$. If the ionic conductances of $Ba^{2+}$ and $SO_4^{2-}$ are $110$ and $136.6 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively,the solubility of $BaSO_4$ at $291 \ K$ will be (Atomic masses: $Ba=137, S=32, O=16$)

Given the following molar conductivities at $25\,\text{}^{\circ}C$: $HCl = 426\,\Omega^{-1}\,cm^{2}\,mol^{-1}$,$NaCl = 126\,\Omega^{-1}\,cm^{2}\,mol^{-1}$,and sodium crotonate $(NaC)$ = $83\,\Omega^{-1}\,cm^{2}\,mol^{-1}$. Calculate the ionization constant $(K_{a})$ of crotonic acid $(HC)$ if the conductivity of a $0.001\,M$ crotonic acid solution is $3.83 \times 10^{-5}\,\Omega^{-1}\,cm^{-1}$.

The $INCORRECT$ statement about the conductivity of electrolytic (ionic) solution is

The conductivity of $0.001 \ M$ acetic acid at a certain temperature is $5.07 \times 10^{-5} \ S \ cm^{-1}$. If $\wedge_m^0$ of acetic acid at the same temperature is $390 \ S \ cm^2 \ mol^{-1}$,the dissociation constant of acetic acid at that temperature is:

What is the conductivity of $0.02 \text{ M}$ $AgNO_3$ solution having cell constant $1.2 \text{ cm}^{-1}$ and resistance $95.0 \text{ }\Omega$?