The correct order of increasing atomic radius | vedclass

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(B) To determine the order of atomic radii,we look at the positions of the elements in the periodic table: $1$. $O$ (Oxygen) and $C$ (Carbon) are in t

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$O < C < S < Se$

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(B) To determine the order of atomic radii,we look at the positions of the elements in the periodic table: $1$. $O$ (Oxygen) and $C$ (Carbon) are in the $2^{nd}$ period. In a period,atomic radius decreases from left to right. Thus,$C > O$. $2$. $S$ (Sulfur) and $Se$ (Selenium) are in the $3^{rd}$ and $4^{th}$ periods respectively. Atomic radius increases down a group. Thus,$Se > S$. $3$. Comparing periods: Elements in the $2^{nd}$ period $(C, O)$ have smaller atomic radii than those in the $3^{rd}$ and $4^{th}$ periods $(S, Se)$. $4$. Combining these: $O Therefore,the correct order of increasing atomic radius is $O < C < S < Se$.

Ion	Radius $(pm)$
$Q^{a+}$	$53$
$X^{b+}$	$66$
$Y^{c+}$	$40$
$Z^{d+}$	$100$

The correct order of increasing atomic radius of the following elements is

Similar Questions

The ionic radii of $N^{3-}$,$O^{2-}$,$F^{-}$,and $Na^{+}$ follow the order:

In the main group elements $(i)$ as we proceed down the same group in the periodic table and $(ii)$ as we proceed from left to right in the same period,the atomic radius

Observe the following data.
Ion Radius $(pm)$
$Q^{a+}$ $53$
$X^{b+}$ $66$
$Y^{c+}$ $40$
$Z^{d+}$ $100$
$Q^{a+}, X^{b+}, Y^{c+}, Z^{d+}$ are respectively

Identify the correct orders regarding atomic radii:
$i$. $Cl > F > Li$
$ii$. $P > C > N$
$iii$. $Tm > Sm > Eu$
$iv$. $Sr > Ca > Mg$

Identify the correct order in which the covalent radius of the following elements increases: $(I) \ Ti, (II) \ Ca, (III) \ Sc$.

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