The correct order of increasing bond angles i | vedclass

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(D) To determine the bond angle,we analyze the hybridization and the number of lone pairs on the central atom:$1$. $ClO_2^-$: The central $Cl$ atom ha

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$ClO_2^- < Cl_2O < ClO_2$

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(D) To determine the bond angle,we analyze the hybridization and the number of lone pairs on the central atom:$1$. $ClO_2^-$: The central $Cl$ atom has $2$ lone pairs and $2$ bond pairs. The bond angle is approximately $111^\circ$.$2$. $Cl_2O$: The central $O$ atom has $2$ lone pairs and $2$ bond pairs. Due to the lower electronegativity of $Cl$ compared to $O$,the bond pairs are further from the central atom,resulting in a smaller bond angle of approximately $110.9^\circ$.$3$. $ClO_2$: The central $Cl$ atom has $1$ lone pair and $2$ bond pairs. With fewer lone pairs,there is less repulsion,leading to a larger bond angle of approximately $117.5^\circ$.Thus,the correct order of increasing bond angles is $ClO_2^- < Cl_2O < ClO_2$.

The correct order of increasing bond angles in the following species is:

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Assertion : Lone pair-lone pair repulsive interactions are greater than lone pair-bond pair and bond pair-bond pair interactions.
Reason : The space occupied by lone pair electrons is more as compared to bond pair electrons.

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