The correct order of ionic radii of trivalent | vedclass

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Question

(C) The ionic radii of trivalent lanthanide ions ($La^{3+}$ to $Lu^{3+}$) decrease due to lanthanide contraction. $La^{3+}$ $(Z=57)$ has the largest r

Vedclass · Accepted Answer

$Y^{3+} < Lu^{3+} < Eu^{3+} < La^{3+}$

Vedclass · Answer

(C) The ionic radii of trivalent lanthanide ions ($La^{3+}$ to $Lu^{3+}$) decrease due to lanthanide contraction. $La^{3+}$ $(Z=57)$ has the largest radius,while $Lu^{3+}$ $(Z=71)$ has the smallest radius among the lanthanides. $Y^{3+}$ $(Z=39)$ is a $4d$ transition metal ion and is significantly smaller than the $4f$ lanthanide ions. Therefore,the order of ionic radii is $Y^{3+} < Lu^{3+} < Eu^{3+} < La^{3+}$.

The correct order of ionic radii of trivalent ions $Y^{3+}$,$La^{3+}$,$Eu^{3+}$,and $Lu^{3+}$ is $(Y=39, La=57, Eu=63, Lu=71)$.

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