The correct order of magnetic moments (spin-o | vedclass

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(C) The magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.$1$. For $[MnCl_4]^

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$[MnCl_4]^{2-} > [CoCl_4]^{2-} > [Fe(CN)_6]^{4-}$

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(C) The magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.$1$. For $[MnCl_4]^{2-}$: $Mn^{2+}$ is $3d^5$. Since $Cl^-$ is a weak field ligand,electrons do not pair up. $n = 5$.$2$. For $[CoCl_4]^{2-}$: $Co^{2+}$ is $3d^7$. Since $Cl^-$ is a weak field ligand,electrons do not pair up. $n = 3$.$3$. For $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $3d^6$. Since $CN^-$ is a strong field ligand,electrons pair up. $n = 0$.Comparing the number of unpaired electrons: $5 > 3 > 0$.Therefore,the order of magnetic moments is $[MnCl_4]^{2-} > [CoCl_4]^{2-} > [Fe(CN)_6]^{4-}$.

The correct order of magnetic moments (spin-only values in $B.M.$) among the following is:
(Atomic numbers: $Mn = 25, Fe = 26, Co = 27$)

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The correct order of magnetic moments (spin-only values in $B.M.$) among the following is:(Atomic numbers: $Mn = 25, Fe = 26, Co = 27$)