The correct order of magnetic moments (spin v | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $Cl^-$ is a weak field ligand,while $CN^-$ is a strong field ligand.$1$. In $[MnCl_4]^{2-}$,$Mn$ is in $+2$ oxidation state ($d^5$ configuration).

Vedclass · Accepted Answer

$[MnCl_4]^{2-} > [CoCl_4]^{2-} > [Fe(CN)_6]^{4-}$

Vedclass · Answer

(D) $Cl^-$ is a weak field ligand,while $CN^-$ is a strong field ligand.$1$. In $[MnCl_4]^{2-}$,$Mn$ is in $+2$ oxidation state ($d^5$ configuration). Since $Cl^-$ is a weak ligand,it has $5$ unpaired electrons.$2$. In $[CoCl_4]^{2-}$,$Co$ is in $+2$ oxidation state ($d^7$ configuration). Since $Cl^-$ is a weak ligand,it has $3$ unpaired electrons.$3$. In $[Fe(CN)_6]^{4-}$,$Fe$ is in $+2$ oxidation state ($d^6$ configuration). Since $CN^-$ is a strong ligand,it forms a low spin complex with $0$ unpaired electrons.The magnetic moment is given by $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.Thus,the order of magnetic moments is $[MnCl_4]^{2-} > [CoCl_4]^{2-} > [Fe(CN)_6]^{4-}$.

The correct order of magnetic moments (spin values in $BM$) among the following is:

Similar Questions

Which of the following will have two stereoisomeric forms?
$I. [Cr(NO_3)_3(NH_3)_3]$
$II. K_3[Fe(C_2O_4)_3]$
$III. [CoCl_2(en)_2]^+$
$IV. [CoBrCl(ox)_2]^{3-}$

What is the spin-only magnetic moment of an element having one unpaired electron (in $BM$)?

Which of the following pairs of compounds has the same number of unpaired electrons?

Which ion has the least value of theoretical magnetic moment?

Arrange the following in the increasing order of the number of unpaired electrons present in the central metal ion:
$I.$ $[MnCl_6]^{3-}$
$II.$ $[FeF_6]^{3-}$
$III.$ $[Mn(CN)_6]^{3-}$
$IV.$ $[Fe(CN)_6]^{3-}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module