The correct order of reactivity of PhMgBr wit | vedclass

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Question

(C) The reactivity of Grignard reagents $(RMgX)$ with carbonyl compounds depends on steric hindrance and the electrophilicity of the carbonyl carbon.$

Vedclass · Accepted Answer

$II > III > I$

Vedclass · Answer

(C) The reactivity of Grignard reagents $(RMgX)$ with carbonyl compounds depends on steric hindrance and the electrophilicity of the carbonyl carbon.$1.$ Aldehydes are generally more reactive than ketones due to less steric hindrance and higher electrophilicity of the carbonyl carbon. Thus,$(II)$ $CH_3-CHO$ is the most reactive.$2.$ Among ketones,as the size of the alkyl or aryl groups increases,steric hindrance increases and reactivity decreases. Also,the $+I$ effect of methyl groups and resonance in phenyl groups reduce the positive charge on the carbonyl carbon.$3.$ $(III)$ $CH_3-CO-CH_3$ (Acetone) is more reactive than $(I)$ $Ph-CO-Ph$ (Benzophenone) because phenyl groups are much bulkier than methyl groups and provide resonance stabilization.Therefore,the correct order is $II > III > I$.

The correct order of reactivity of $PhMgBr$ with: $(I)$ $Ph-CO-Ph$,$(II)$ $CH_3-CHO$,$(III)$ $CH_3-CO-CH_3$ is:

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