The correct order of reducing abilities of hy | vedclass

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(A) The reducing character of the hydrides of group $15$ elements depends upon the thermal stability of the $E-H$ bond. As we move down the group,the

Vedclass · Accepted Answer

$NH_3 < PH_3 < AsH_3 < SbH_3 < BiH_3$

Vedclass · Answer

(A) The reducing character of the hydrides of group $15$ elements depends upon the thermal stability of the $E-H$ bond. As we move down the group,the bond dissociation enthalpy decreases due to an increase in the size of the central atom. Consequently,the stability of the hydrides decreases,and the ease of releasing hydrogen atoms increases. Therefore,the reducing character increases down the group. The correct order is: $NH_3 < PH_3 < AsH_3 < SbH_3 < BiH_3$.

$a$. Pure nitrogen	$i$. Chlorine
$b$. Haber process	$ii$. Sulphuric acid
$c$. Contact process	$iii$. Ammonia
$d$. Deacon's process	$iv$. Sodium azide or Barium azide

The correct order of reducing abilities of hydrides of group $15$ elements is:

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Match the following:

$a$. Pure nitrogen $i$. Chlorine

$b$. Haber process $ii$. Sulphuric acid

$c$. Contact process $iii$. Ammonia

$d$. Deacon's process $iv$. Sodium azide or Barium azide

Which of the following is the correct option?

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