The correct order of the oxidation states of nitrogen in $NO$,$N_2O$,$NO_2$,and $N_2O_3$ is:
- A$N_2O < N_2O_3 < NO < NO_2$
- B$NO_2 < NO < N_2O_3 < N_2O$
- C$NO_2 < N_2O_3 < NO < N_2O$
- D$N_2O < NO < N_2O_3 < NO_2$
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The oxidation number of $S$ in $Na_2S_4O_6$ is ...........
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$\underline{K}O_2$,$H_2\underline{O}_2$ and $H_2\underline{S}O_4$.
The oxidation states of the underlined elements in them are,respectively,
$\underline{K}O_2$,$H_2\underline{O}_2$ and $H_2\underline{S}O_4$.
The oxidation states of the underlined elements in them are,respectively,
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View SolutionWhat is the oxidation number of $S$ in $H_2S_2O_8$?
What is the oxidation state of $S$ in the sulphur-containing product of the following reaction?
$SO_3^{2-}{_{\text{(aq)}}} + Br_{2\text{(l)}} + H_2O_{\text{(l)}} \rightarrow $
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