(A) The reaction sequence is as follows:$1$. Dehydrogenation of heptane $(P)$ using $Cr_2O_3$ at $770 \ K$ and $20 \ atm$ yields toluene.$2$. Etard re

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$(i) Cr_2O_3, 770 \ K, 20 \ atm$; $(ii) CrO_2Cl_2, H_3O^{+}$; $(iii) NaOH$; $(iv) H_3O^{+}$

(A) The reaction sequence is as follows:$1$. Dehydrogenation of heptane $(P)$ using $Cr_2O_3$ at $770 \ K$ and $20 \ atm$ yields toluene.$2$. Etard reaction of toluene with $CrO_2Cl_2$ followed by hydrolysis gives benzaldehyde.$3$. Benzaldehyde undergoes Cannizzaro reaction with $NaOH$ to form sodium benzoate and benzyl alcohol.$4$. Acidification with $H_3O^{+}$ converts sodium benzoate to benzoic acid $(Q)$ and leaves benzyl alcohol $(R)$.

Class 12 Chemistry 8-1.Aldehydes and Ketones Properties

Medium

The correct sequence of reagents for the preparation of $Q$ and $R$ is:

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A
$(i) Cr_2O_3, 770 \ K, 20 \ atm$; $(ii) CrO_2Cl_2, H_3O^{+}$; $(iii) NaOH$; $(iv) H_3O^{+}$
B
$(i) CrO_2Cl_2, H_3O^{+}$; $(ii) Cr_2O_3, 770 \ K, 20 \ atm$; $(iii) NaOH$; $(iv) H_3O^{+}$
C
$(i) KMnO_4, OH^{-}$; $(ii) Mo_2O_3, \Delta$; $(iii) NaOH$; $(iv) H_3O^{+}$
D
$(i) Mo_2O_3, \Delta$; $(ii) CrO_2Cl_2, H_3O^{+}$; $(iii) NaOH$; $(iv) H_3O^{+}$