The correct sequential order of the reagents | vedclass

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(B) The starting material is $p$-nitroaniline. The goal is to convert the $-NO_2$ group to $-OH$ and the $-NH_2$ group to $-I$. $1$. First,treat $p$-n

Vedclass · Accepted Answer

$HNO_2, KI, Fe/H^{+}, HNO_2, H_2O/	ext{warm}$

Vedclass · Answer

(B) The starting material is $p$-nitroaniline. The goal is to convert the $-NO_2$ group to $-OH$ and the $-NH_2$ group to $-I$. $1$. First,treat $p$-nitroaniline with $HNO_2$ ($NaNO_2 + HCl$ at $0-5^{\circ}C$) to form the diazonium salt at the $-NH_2$ position. $2$. Then,treat with $KI$ to replace the diazonium group with $-I$. $3$. Next,reduce the $-NO_2$ group to $-NH_2$ using $Fe/H^{+}$. $4$. Treat with $HNO_2$ again to convert the new $-NH_2$ group into a diazonium salt. $5$. Finally,heat with $H_2O$ to convert the diazonium group into an $-OH$ group. This corresponds to the sequence: $HNO_2, KI, Fe/H^{+}, HNO_2, H_2O/	ext{warm}$.

The correct sequential order of the reagents for the given reaction is:

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