The correct set of four quantum numbers for t | vedclass

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Question

(A) The atomic number of rubidium $(Rb)$ is $37$.The electronic configuration of $Rb$ is $[Kr] 5s^1$.The valence electron is in the $5s$ orbital.For t

Vedclass · Accepted Answer

$n=5, l=0, m=0, s=+\frac{1}{2}$

Vedclass · Answer

(A) The atomic number of rubidium $(Rb)$ is $37$.The electronic configuration of $Rb$ is $[Kr] 5s^1$.The valence electron is in the $5s$ orbital.For the $5s$ orbital:Principal quantum number $(n) = 5$.Azimuthal quantum number $(l) = 0$ (for $s$-orbital).Magnetic quantum number $(m) = 0$.Spin quantum number $(s) = +\frac{1}{2}$ or $-\frac{1}{2}$.Thus,the correct set is $(n=5, l=0, m=0, s=+\frac{1}{2})$.

The correct set of four quantum numbers for the valence electron of rubidium atom $(Z=37)$ is:

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