The correct set of four quantum numbers for t | vedclass

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Question

(A) The atomic number of strontium $(Sr)$ is $38$. The electronic configuration is $[Kr] 5s^2$.The valence electrons are present in the $5s$ orbital.F

Vedclass · Accepted Answer

$n=5, l=0, m_l=0, m_s=+\frac{1}{2}$

Vedclass · Answer

(A) The atomic number of strontium $(Sr)$ is $38$. The electronic configuration is $[Kr] 5s^2$.The valence electrons are present in the $5s$ orbital.For the $5s$ orbital:Principal quantum number $(n) = 5$.Azimuthal quantum number $(l) = 0$ (for $s$-orbital).Magnetic orbital quantum number $(m_l) = 0$.Electron spin quantum number $(m_s) = +\frac{1}{2}$ or $-\frac{1}{2}$.Thus,the correct set of quantum numbers is $n=5, l=0, m_l=0, m_s=+\frac{1}{2}$.

List-$A$	List-$B$
$(1)$ Principal quantum number	$(A)$ Shape of the orbital
$(2)$ Azimuthal quantum number	$(B)$ Spin of the electron
$(3)$ Magnetic quantum number	$(C)$ Orientation of the orbital in space
$(4)$ Spin quantum number	$(D)$ Size of the orbital

The correct set of four quantum numbers for the valence electron of strontium $(Z=38)$ is:

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