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(C) The atomic number of chlorine $(Cl)$ is $17$.The electronic configuration of $Cl$ is $1s^2 2s^2 2p^6 3s^2 3p^5$.The valence shell configuration is

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$3, 1, 1$

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(C) The atomic number of chlorine $(Cl)$ is $17$.The electronic configuration of $Cl$ is $1s^2 2s^2 2p^6 3s^2 3p^5$.The valence shell configuration is $3s^2 3p^5$.In the $3p$ subshell,there are $3$ orbitals $(3p_x, 3p_y, 3p_z)$. According to Hund's rule,the $5$ electrons are filled as follows: $3p_x^2, 3p_y^2, 3p_z^1$.The unpaired electron is in the $3p_z$ orbital.For this electron:Principal quantum number $(n)$ = $3$Azimuthal quantum number $(l)$ for $p$-orbital = $1$Magnetic quantum number $(m)$ can be $-1, 0, +1$. By convention,the unpaired electron is often assigned $m = +1$.Thus,the set of quantum numbers is $n=3, l=1, m=1$.

The correct set of quantum numbers for the unpaired electron of a chlorine atom is:

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