The correct solubility order is/are:I. CaCO_3 | vedclass

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(D) For alkaline earth metal carbonates $(Group \ 2)$,the solubility decreases down the group because the lattice energy decreases less rapidly than t

Vedclass · Accepted Answer

$I, II, III$

Vedclass · Answer

(D) For alkaline earth metal carbonates $(Group \ 2)$,the solubility decreases down the group because the lattice energy decreases less rapidly than the hydration energy as the cation size increases. Thus,the order is $BeCO_3 > MgCO_3 > CaCO_3 > SrCO_3 > BaCO_3$. Statement $I$ is correct.For alkali metal carbonates $(Group \ 1)$,the solubility increases down the group because the hydration energy decreases less rapidly than the lattice energy as the cation size increases. Thus,the order is $Li_2CO_3 Statement $IV$ is incorrect as it contradicts the trend for alkali metal carbonates.Therefore,the correct statements are $I, II, III$.

List-$I$ Elements	List-$II$ Colour imparted to the flame
$A. K$	$I. Violet$
$B. Ca$	$II. Brick Red$
$C. Sr$	$III. Crimson Red$
$D. Ba$	$IV. Apple Green$

The correct solubility order is/are:
$I. CaCO_3 > SrCO_3 > BaCO_3$
$II. Li_2CO_3 < Na_2CO_3 < K_2CO_3$
$III. K_2CO_3 < Rb_2CO_3 < Cs_2CO_3$
$IV. Na_2CO_3 > K_2CO_3 > Rb_2CO_3$

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Match List-$I$ with List-$II$

List-$I$ Elements List-$II$ Colour imparted to the flame

$A. K$ $I. Violet$

$B. Ca$ $II. Brick Red$

$C. Sr$ $III. Crimson Red$

$D. Ba$ $IV. Apple Green$

Choose the correct answer from the options given below:

Which of the following conduct electricity in the fused state?

The pair$(s)$ of reagents that yield paramagnetic species is/are:
$A$. $Na$ and excess of $NH_3$
$B$. $K$ and excess of $O_2$
$C$. $Cu$ and dilute $HNO_3$
$D$. $O_2$ and $2-ethylanthraquinol$

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The correct solubility order is/are:$I. CaCO_3 > SrCO_3 > BaCO_3$$II. Li_2CO_3 < Na_2CO_3 < K_2CO_3$$III. K_2CO_3 < Rb_2CO_3 < Cs_2CO_3$$IV. Na_2CO_3 > K_2CO_3 > Rb_2CO_3$