The correct stability order for the following | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The stability of carbocations is determined by resonance,hyperconjugation,and inductive effects.$(I)$ is a tertiary carbocation adjacent to an oxy

Vedclass · Accepted Answer

$(I) > (III) > (II) > (IV)$

Vedclass · Answer

(D) The stability of carbocations is determined by resonance,hyperconjugation,and inductive effects.$(I)$ is a tertiary carbocation adjacent to an oxygen atom. It is stabilized by resonance (lone pair donation from oxygen) and has $6$ $\alpha$-hydrogen atoms for hyperconjugation.$(III)$ is a secondary carbocation adjacent to an oxygen atom. It is stabilized by resonance,but has only $3$ $\alpha$-hydrogen atoms.$(II)$ is a secondary alkyl carbocation with $5$ $\alpha$-hydrogen atoms.$(IV)$ is a primary alkyl carbocation with $2$ $\alpha$-hydrogen atoms.Resonance stabilization by the oxygen atom is the most significant factor,making $(I)$ and $(III)$ more stable than $(II)$ and $(IV)$. Between $(I)$ and $(III)$,$(I)$ is more stable due to more hyperconjugation. Between $(II)$ and $(IV)$,$(II)$ is more stable due to more hyperconjugation.Therefore,the correct stability order is $(I) > (III) > (II) > (IV)$.

The correct stability order for the following species is:

Similar Questions

The decreasing order of stability of the given carbocations is

Which is the most stable carbocation?

Based upon an understanding of product stability,predict the product formed when the following dianion reacts with one equivalent of acid $(H^+)$.

Due to the presence of an unpaired electron,free radicals are .........

In which of the following compounds,the $C-Cl$ bond ionisation shall give the most stable carbonium ion?

Vedclass Test Series

Exam Paper Generator

Online Exam Module