The correct stability order of the given cano | vedclass

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(B) The stability of resonance structures is determined by the following rules:$1$. Structures with complete octets for all atoms are more stable.$2$.

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$III > I > II$

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(B) The stability of resonance structures is determined by the following rules:$1$. Structures with complete octets for all atoms are more stable.$2$. Structures with fewer formal charges are more stable.$3$. Negative charge on a more electronegative atom and positive charge on a less electronegative atom is more stable.In structure $I$,all atoms have a complete octet,but there is a positive charge on the oxygen atom $(O^{\oplus})$.In structure $II$,the carbon atom has an incomplete octet (carbocation),making it the least stable.In structure $III$,all atoms have a complete octet,and the positive charge is on the nitrogen atom $(N^{\oplus})$.Since nitrogen is less electronegative than oxygen,it can better accommodate the positive charge. Therefore,$III$ is more stable than $I$.The overall stability order is $III > I > II$.

The correct stability order of the given canonical structures is:

Similar Questions

Which of the following is the least stable?

Resonance effect is not observed in

For the given compounds,the correct order of resonance energy is:
$(I)$ $CH_2=CH-CH=CH-OCH_3$
$(II)$ $CH_2=CH-C(OCH_3)=CH_2$
$(III)$ $CH_2=CH-OCH_3$

The order of relative stability of the contributing structures is:
$I: CH_2=CH-CHO$
$II: ^+CH_2-CH=CH-O^-$
$III: ^-CH_2-CH=CH-O^+$
Choose the correct answer from the options given below:

The correct order of decreasing length of the bond as indicated by the arrow in the following structures is:

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