The correct statement about Cr^{2+} and Mn^{3 | vedclass

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Question

(A) $Cr^{2+}$ has the electronic configuration $[Ar] 3d^4$. It acts as a reducing agent because it gets oxidized to $Cr^{3+}$ $([Ar] 3d^3)$,which is m

Vedclass · Accepted Answer

$Cr^{2+}$ is a reducing agent

Vedclass · Answer

(A) $Cr^{2+}$ has the electronic configuration $[Ar] 3d^4$. It acts as a reducing agent because it gets oxidized to $Cr^{3+}$ $([Ar] 3d^3)$,which is more stable due to the half-filled $t_{2g}$ orbital.$Mn^{3+}$ has the electronic configuration $[Ar] 3d^4$. It acts as an oxidizing agent because it gets reduced to $Mn^{2+}$ $([Ar] 3d^5)$,which is more stable due to the half-filled $d$-orbital.Therefore,$Cr^{2+}$ is a reducing agent,while $Mn^{3+}$ is an oxidizing agent.Thus,the correct statement is that $Cr^{2+}$ is a reducing agent.

The correct statement about $Cr^{2+}$ and $Mn^{3+}$ among the following is (Given,atomic numbers of $Cr=24$ and $Mn=25$)

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