The correct structures of A and B formed in t | vedclass

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(D) $1$. The first step is the reduction of $p$-nitrophenol using $H_2/Pd$ in $C_2H_5OH$. The nitro group $(-NO_2)$ is reduced to an amino group $(-NH

Vedclass · Accepted Answer

$A$: $p$-aminophenol,$B$: $N$-($4$-acetoxyphenyl)acetamide

Vedclass · Answer

(D) $1$. The first step is the reduction of $p$-nitrophenol using $H_2/Pd$ in $C_2H_5OH$. The nitro group $(-NO_2)$ is reduced to an amino group $(-NH_2)$,yielding $p$-aminophenol as product $A$.$2$. In the second step,$p$-aminophenol reacts with $1.0$ equivalent of acetic anhydride. The amino group $(-NH_2)$ is more nucleophilic than the phenolic hydroxyl group $(-OH)$. Therefore,the amino group undergoes nucleophilic acyl substitution $(S_N AE)$ with acetic anhydride to form $N$-($4$-hydroxyphenyl)acetamide (also known as $p$-acetamidophenol) as the major product $B$.

The correct structures of $A$ and $B$ formed in the following reactions are:

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