The critical temperatures of gases A, B, C, a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The extent of physical adsorption of a gas on a solid surface is directly proportional to its ease of liquefaction.Easier liquefaction is indicate

Vedclass · Accepted Answer

$A$

Vedclass · Answer

(D) The extent of physical adsorption of a gas on a solid surface is directly proportional to its ease of liquefaction.Easier liquefaction is indicated by a higher critical temperature $(T_c)$.Therefore,gases with higher critical temperatures are adsorbed to a greater extent.The critical temperatures are: $B (630 \ K) > D (400 \ K) > C (261 \ K) > A (190 \ K)$.Thus,the order of adsorption is $B > D > C > A$.The gas with the lowest critical temperature will have the least amount adsorbed.Hence,gas $A$ has the least quantity adsorbed.

The critical temperatures of gases $A, B, C,$ and $D$ are $190 \ K, 630 \ K, 261 \ K,$ and $400 \ K$ respectively. The quantity of gas adsorbed per gram of charcoal at the same pressure is least for the gas:

Similar Questions

For the adsorption of a gas on a solid,the slope of the linear plot of $\log(x/m)$ versus $\log(p)$ is .... ($n$ is an integer).

Assertion $(A)$: The property of adsorption is shown to a greater extent by solids than liquids.
Reason $(R)$: Solids like charcoal and silica can act as good adsorbents.

Assertion $(A)$: van der Waals' forces are responsible for chemisorption.
Reason $(R)$: High temperature is favourable for chemisorption.
The correct answer is

The adsorption of a gas on the surface of a solid is generally an exothermic process because ......

The shape of the adsorption isobar for physical adsorption and the adsorption isobar for chemisorption, respectively, are:

Vedclass Test Series

Exam Paper Generator

Online Exam Module