The current amplification factor and the collector current in a $CE$ transistor circuit are $100$ and $2.2 \text{ mA}$ respectively. Then the base current is (in $\mu A$)

In a $CE$ transistor amplifier,the signal voltage across the collector resistance is $2.5 \ V$. The input signal voltage is $0.02 \ V$. If the base and collector resistances are $1.5 \ k\Omega$ and $2.5 \ k\Omega$,then the current amplification factor is

$A$ transistor is used as an amplifier in a common-base configuration. The load resistance is $5 \text{ k}\Omega$, the current gain is $0.98$, and the input resistance is $70 \Omega$. The voltage gain and power gain are, respectively:

For a transistor,$\beta = 100$. The value of $\alpha$ is

In a common base circuit of a transistor,the amplification factor is $0.95.$ The base current when the emitter current is $2\,mA,$ is ....$mA$

$A$ $npn$ transistor is connected in common emitter configuration in a given amplifier. $A$ load resistance of $800 \,\,\Omega$ is connected in the collector circuit and the voltage drop across it is $0.8 \,\, V$. If the current amplification factor is $0.96$ and the input resistance of the circuit is $192 \,\,\Omega$,the voltage gain and the power gain of the amplifier will respectively be