The current flowing in a coil of self-inducta | vedclass

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(D) The induced $e.m.f.$ $(e)$ in a coil due to self-induction is given by the formula: $e = -L \frac{di}{dt}$.Given:Self-inductance $L = 0.4 \, mH =

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$- 1 \, mV$

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(D) The induced $e.m.f.$ $(e)$ in a coil due to self-induction is given by the formula: $e = -L \frac{di}{dt}$.Given:Self-inductance $L = 0.4 \, mH = 0.4 	imes 10^{-3} \, H$.Change in current $di = 250 \, mA = 250 	imes 10^{-3} \, A$.Time interval $dt = 0.1 \, s$.Substituting these values into the formula:$e = -(0.4 	imes 10^{-3} \, H) 	imes \frac{250 	imes 10^{-3} \, A}{0.1 \, s}$.$e = -(0.4 	imes 10^{-3}) 	imes (2500 	imes 10^{-3})$.$e = -1000 	imes 10^{-6} \, V$.$e = -1 	imes 10^{-3} \, V = -1 \, mV$.Therefore,the induced $e.m.f.$ is $-1 \, mV$.

The current flowing in a coil of self-inductance $0.4 \, mH$ is increased by $250 \, mA$ in $0.1 \, s$. The induced $e.m.f.$ will be:

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